Matematika Q.

5!=
23+5=
6×7=
7!=

pakek cara​

Q.

5!=
23+5=
6×7=
7!=

pakek cara​

Penyelesaian:

5!

=5×4×3×2×1

=20×6

=120

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23+5

=28

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6×7

=7+7+7+7+7+7

=14+14+14

=28+14

=42

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7!

=7×6×5×4×3×2×1

=42×5×4×3×2×1

=210×4×3×2×1

=840×3×2×1

=2.520×2×1

=5.040×1

=5.040

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[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]

Materi : Bentuk Akar dan Pangkat

5!

= 5 × 4 × 3 × 2 × 1

= 20 × 6

= 120

23 + 5

= 20 + 3 + 5

= 20 + 8

= 28

6 × 7

= 7 + 7 + 7 + 7 + 7 + 7

= 14 + 14 + 14

= 10 + 10 + 10 + 4 + 4 + 4

= 20 + 10 + 8 + 4

= 30 + 12

= 42

7!

= 7 × 6 × 5 × 4 × 3 × 2 × 1

= 42 × 20 × 6

= 42 × 120

= 4.200 + 840

= 5.040

Semoga bisa membantu

[tex] \boxed{ \colorbox{lightblue}{ \sf{ \color{blue}{ Answer By\:BlueBraxGeometry}}}} [/tex]

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